In the given reaction cycle,X,Y and Z respect | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The reaction between $CaCl_2$ and $Na_2CO_3$ is a double displacement reaction:$CaCl_2 + Na_2CO_3 \rightarrow CaCO_3(s) + 2NaCl(aq)$Comparing this

Vedclass · Accepted Answer

$CaCO_3, NaCl, HCl$

Vedclass · Answer

(C) The reaction between $CaCl_2$ and $Na_2CO_3$ is a double displacement reaction:$CaCl_2 + Na_2CO_3 \rightarrow CaCO_3(s) + 2NaCl(aq)$Comparing this with the given reaction $CaCl_2 + Na_2CO_3 \rightarrow X + Y$,we identify $X$ as $CaCO_3$ and $Y$ as $NaCl$.To convert $CaCO_3$ back to $CaCl_2$,it is reacted with hydrochloric acid $(HCl)$:$CaCO_3 + 2HCl \rightarrow CaCl_2 + H_2O + CO_2$Thus,$Z$ is $HCl$.Therefore,$X = CaCO_3$,$Y = NaCl$,and $Z = HCl$.

In the given reaction cycle,$X$,$Y$ and $Z$ respectively are:
$CaCl_2 + Na_2CO_3 \rightarrow X + Y$
$X \xrightarrow{Z} CaCl_2$

Similar Questions

Beryllium shows a diagonal relationship with aluminum. Which of the following similarities is incorrect?

Which of the following metal carbides gives propyne or allylene upon hydrolysis?

Which of the following sulphates has the highest solubility in water?

Among the following,which is water insoluble?

From which of the following reactions can anhydrous $MgCl_2$ be prepared?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

In the given reaction cycle,$X$,$Y$ and $Z$ respectively are:$CaCl_2 + Na_2CO_3 \rightarrow X + Y$$X \xrightarrow{Z} CaCl_2$