In the given reaction sequence:
$CH_3-CH_2-OH$ $\xrightarrow[(ii) H^{\oplus}]{(i) KMnO_4/OH^{\ominus}/\Delta} (A)$ $\xrightarrow[(ii) NH_3/\Delta]{(i) SOCl_2} (B)$ $\xrightarrow{Br_2/KOH} (C)$
$(C)$ will be:

$A$ student performed an analysis of an aliphatic organic compound '$X$' which, upon analysis, gave $C=61.01\%$, $H=15.25\%$, $N=23.74\%$. This compound, on treatment with $HNO_2/H_2O$, produced another compound '$Y$' which did not contain any nitrogen atom. However, the compound '$Y$' upon controlled oxidation produced another compound '$Z$' that responded to the iodoform test. The structure of '$X$' is:

Identify the products $y$ and $x$ in the following reaction sequence:
$C_6H_5CONH_2 \xrightarrow{NaOBr} y$
$C_6H_5CONH_2 \xrightarrow[(ii) H_3O^+]{(i) C_6H_5SO_2Cl / py, \Delta} x$

Acetamide is

Choose the incorrect option:

Given below are two statements:
Statement $I$: Aniline does not undergo Friedel-Crafts alkylation reaction.
Statement $II$: Aniline cannot be prepared through Gabriel synthesis.
In the light of the above statements,choose the correct answer from the options given below: