In the given reaction $C_6H_5CHO + X \xrightarrow{(i) Zn, (ii) HOH/NH_4Cl} C_6H_5-CH(OH)-CH_2-COOC_2H_5$,$[X]$ will be:
- A$CH_3-COOC_2H_5$
- B$CH_3-CH_2-COOC_2H_5$
- C$Br-CH_2-COOC_2H_5$
- D$Br_2CH-COOC_2H_5$
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The major product of the following reaction is
MediumNEET 2025
View Solution$CH_3CH_2COCH_3 \xrightarrow{NaNO_2/HCl}$ Major product of this reaction is
Difficult
View Solution$CH_3-CH(OH)-CH_2-CHO$
$3HCHO + A \xrightarrow[40^o C]{Na_2CO_3} (B) (82\%)$
Product $(B)$ of the above reaction is
$3HCHO + A \xrightarrow[40^o C]{Na_2CO_3} (B) (82\%)$
Product $(B)$ of the above reaction is
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View Solution$(A)$ and $(B)$ in the following reaction sequence are:
$RR'C=O$ $\xrightarrow{HCN} (A)$ $\xrightarrow{B} RR'C(OH)CH_2NH_2$
$RR'C=O$ $\xrightarrow{HCN} (A)$ $\xrightarrow{B} RR'C(OH)CH_2NH_2$
Difficult
View SolutionWhich of the following compounds will give a silver mirror test with ammoniacal silver nitrate (Tollens' reagent)?
$(A)$ Formic acid
$(B)$ Formaldehyde
$(C)$ Benzaldehyde
$(D)$ Acetone
Choose the correct answer from the options given below:
$(A)$ Formic acid
$(B)$ Formaldehyde
$(C)$ Benzaldehyde
$(D)$ Acetone
Choose the correct answer from the options given below:
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