In the given transistor circuit,the base current is $35 \mu A$. The value of $R_b$ is.....$k\Omega$.

For a transistor,$\alpha_{dc}$ and $\beta_{dc}$ are the current ratios,then the value of $\frac{\beta_{dc}-\alpha_{dc}}{\alpha_{dc} \times \beta_{dc}}$ is:

$A$ change of $0.04 \ V$ takes place between the base and the emitter when an input signal is connected to the common emitter transistor amplifier. As a result,a $20 \ \mu A$ change takes place in the base current and a change of $2 \ mA$ takes place in the collector current. The input resistance and $AC$ current gain are:

$A$ transistor is used as a common emitter amplifier with a load resistance $2 \ k\Omega$. The input resistance is $150 \ \Omega$. The base current is changed by $20 \ \mu A$,which results in a change in collector current by $1.5 \ mA$. The voltage gain of the amplifier is

$NPN$ transistors are preferred to $PNP$ transistors because they have

While a collector to emitter voltage is constant in a transistor, the collector current changes by $8.2 \,mA$ when the emitter current changes by $8.3 \,mA$. The value of forward current ratio is