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(C) The given circuit consists of a $NOR$ gate followed by an $AND$ gate.Inputs $B$ and $C$ are fed into a $NOR$ gate,which produces an output $X = \o

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when $A=1, B=0, C=0$.

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(C) The given circuit consists of a $NOR$ gate followed by an $AND$ gate.Inputs $B$ and $C$ are fed into a $NOR$ gate,which produces an output $X = \overline{B+C}$.This output $X$ and input $A$ are then fed into an $AND$ gate to produce the final output $Y$.Therefore,the Boolean expression for the output is $Y = A \cdot X = A \cdot (\overline{B+C})$.For the output $Y$ to be $HIGH$ $(Y=1)$,both $A$ must be $1$ and $(\overline{B+C})$ must be $1$.$(\overline{B+C}) = 1$ only when $B+C = 0$,which means $B=0$ and $C=0$.Thus,$Y=1$ when $A=1, B=0, C=0$.

In the logic circuit given,$A, B$ and $C$ are the inputs and $Y$ is the output. The output $Y$ is $HIGH$ when:

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