In the network shown below,the charge accumulated in the capacitor in steady state will be ........... $\mu C$.

If a capacitor of capacitance $100 \mu F$ is charged at a steady rate of $100 \mu C s^{-1}$,then the time taken to produce a potential difference of $100 \ V$ between the capacitor plates is (in $s$)

Twenty-seven drops of the same size are charged at $220 \, V$ each. They combine to form a bigger drop. Calculate the potential of the bigger drop (in $V$).

Two neutral conducting spheres of diameters $8 \ cm$ and $2 \ cm$ separated with a distance of $15 \ cm$ between their centres are joined by a thin conducting wire. $A$ charge of $100 \ nC$ is given to one of the spheres and the system is allowed to reach electrostatic equilibrium. The electric potential at a point on the line joining the centres of the two spheres where the net electric field becomes zero is . . . . . . $V$. (Neglect the charge acquired by the wire and $\frac{1}{4 \pi \varepsilon_0}=9 \times 10^9 \ Nm^2 C^{-2}$)

In the figure shown below,the charge on the left plate of the $10\, \mu F$ capacitor is $-30\,\mu C.$ The charge on the right plate of the $6\,\mu F$ capacitor is.....$\mu C$.

$n$ identical droplets are charged to $V$ volt each. If they coalesce to form a single drop, then its potential will be