(A) For the given nuclear reaction: $_{92}U^{238} \to _{82}Pb^{206} + x\,_{2}He^{4} + y\,_{-1}\beta^{0}$$1$. Balancing the mass number: $238 = 206 + 4

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(A) For the given nuclear reaction: $_{92}U^{238} \to _{82}Pb^{206} + x\,_{2}He^{4} + y\,_{-1}\beta^{0}$$1$. Balancing the mass number: $238 = 206 + 4x + 0y \implies 4x = 32 \implies x = 8$.$2$. Balancing the atomic number: $92 = 82 + 2x - y \implies 92 = 82 + 2(8) - y \implies 92 = 82 + 16 - y \implies 92 = 98 - y \implies y = 6$.Therefore,the values are $x = 8$ and $y = 6$.

Class 12 Chemistry Nuclear Chemistry Artificial transmutation

Medium

In the nuclear reaction $_{92}U^{238} \to _{82}Pb^{206} + x\,_{2}He^{4} + y\,_{-1}\beta^{0}$,the values of $x$ and $y$ are respectively......

A
$8, 6$
B
$6, 4$
C
$6, 8$
D
$8, 10$

Explore More

Browse All

Question Bank

All Subjects

Class 12 Questions

Class 12

Chemistry Questions

Chapter

Nuclear Chemistry

Subtopic

Artificial transmutation

$_6C^{12}$ and $_1T^3$ are formed in nature due to the nuclear reaction of a neutron with:

MediumAP EAMCET 2004

View Solution

In the following nuclear reactions $_7N^{14} + _2He^4 \to _8O^{17} + X_1$ and $_{13}Al^{27} + _1D^2 \to _{14}Si^{28} + X_2$,$X_1$ and $X_2$ are respectively:

Medium

View Solution

Which one of the following nuclear transformations is of the $(n, p)$ type?

MediumAIIMS 1980

View Solution

In the nuclear reaction $_{12}Mg^{24} + _{2}He^{4} = _{0}n^{1} + ?$,the product nucleus is:

Medium

View Solution

What is $X$ in the following reaction?
${}_{12}Mg^{26} + {}_{1}H^{2} \longrightarrow {}_{12}Mg^{27} + X$

MediumTS EAMCET 2001

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

In the nuclear reaction $_{92}U^{238} \to _{82}Pb^{206} + x\,_{2}He^{4} + y\,_{-1}\beta^{0}$,the values of $x$ and $y$ are respectively......

Similar Questions

$_6C^{12}$ and $_1T^3$ are formed in nature due to the nuclear reaction of a neutron with:

In the following nuclear reactions $_7N^{14} + _2He^4 \to _8O^{17} + X_1$ and $_{13}Al^{27} + _1D^2 \to _{14}Si^{28} + X_2$,$X_1$ and $X_2$ are respectively:

Which one of the following nuclear transformations is of the $(n, p)$ type?

In the nuclear reaction $_{12}Mg^{24} + _{2}He^{4} = _{0}n^{1} + ?$,the product nucleus is:

What is $X$ in the following reaction?${}_{12}Mg^{26} + {}_{1}H^{2} \longrightarrow {}_{12}Mg^{27} + X$

Vedclass Test Series

Exam Paper Generator

Online Exam Module

What is $X$ in the following reaction?
${}_{12}Mg^{26} + {}_{1}H^{2} \longrightarrow {}_{12}Mg^{27} + X$