In the nuclear transmutation _4^9 Be + X long | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The given nuclear reaction is $_4^9 Be + X \longrightarrow _4^8 Be + Y$.For the reaction to be balanced,the sum of atomic numbers and mass numbers

Vedclass · Accepted Answer

$(A) (\gamma, n)$

Vedclass · Answer

(A) The given nuclear reaction is $_4^9 Be + X \longrightarrow _4^8 Be + Y$.For the reaction to be balanced,the sum of atomic numbers and mass numbers must be conserved on both sides.Case $1$: If $X = \gamma$ (photon,$0^0\gamma$),then $_4^9 Be + _0^0\gamma \longrightarrow _4^8 Be + _0^1 n$. Here $Y = n$ (neutron).Case $2$: If $X = p$ (proton,$_1^1 p$),then $_4^9 Be + _1^1 p \longrightarrow _4^8 Be + _1^2 D$. Here $Y = D$ (deuteron).Thus,both $(A)$ and $(B)$ are valid pairs for $(X, Y)$.

In the nuclear transmutation $_4^9 Be + X \longrightarrow _4^8 Be + Y$,the pair $(X, Y)$ is (are):

Similar Questions

When $_3Li^7$ are bombarded with protons,$\gamma$-rays are produced. The nuclide formed is

$_6C^{12}$ and $_1T^3$ are formed in nature due to the nuclear reaction of a neutron with:

The missing particle in the reaction,$_{92}^{235}U + _{0}^{1}n \to _{56}^{146}Ba + ... + 3_{0}^{1}n$ is

An artificial radioactive isotope gave $_7^{14}N$ after two successive $\beta$-particle emissions. The number of neutrons in the parent nucleus must be

Which of the following is an example of nuclear fusion?

Vedclass Test Series

Exam Paper Generator

Online Exam Module