In the organic compound CH_2=CH-CH_2-CH_2-Ceq | vedclass

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(D) The structure of the compound is $\overset{6}{C}H_2 = \overset{5}{C}H - \overset{4}{C}H_2 - \overset{3}{C}H_2 - \overset{2}{C} \equiv \overset{1}{

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$sp-sp^3$

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(D) The structure of the compound is $\overset{6}{C}H_2 = \overset{5}{C}H - \overset{4}{C}H_2 - \overset{3}{C}H_2 - \overset{2}{C} \equiv \overset{1}{C}H$. Assigning hybridization to each carbon atom: $C_1$ is $sp$ hybridized. $C_2$ is $sp$ hybridized. $C_3$ is $sp^3$ hybridized. $C_4$ is $sp^3$ hybridized. $C_5$ is $sp^2$ hybridized. $C_6$ is $sp^2$ hybridized. The $C_2-C_3$ bond is formed by the overlap of an $sp$ hybridized orbital of $C_2$ and an $sp^3$ hybridized orbital of $C_3$. Therefore,the pair of hybridized orbitals is $sp-sp^3$.

List-$I$	List-$II$
$A$. Ethane	$1$. $2 \ sp$ carbons
$B$. Ethylene	$2$. $6 \ sp^2$ carbons
$C$. Acetylene	$3$. $2 \ sp^3$ carbons
$D$. Benzene	$4$. $2 \ sp^2$ carbons
	$5$. $1 \ sp$ and $1 \ sp^2$ carbons

In the organic compound $CH_2=CH-CH_2-CH_2-C\equiv CH$,the pair of hybridized orbitals involved in the formation of the $C_2-C_3$ bond is:

Similar Questions

In which of the following compounds is the underlined carbon atom $sp^3$ hybridized?

Match the following lists:
List-$I$ List-$II$
$A$. Ethane $1$. $2 \ sp$ carbons
$B$. Ethylene $2$. $6 \ sp^2$ carbons
$C$. Acetylene $3$. $2 \ sp^3$ carbons
$D$. Benzene $4$. $2 \ sp^2$ carbons
$5$. $1 \ sp$ and $1 \ sp^2$ carbons

The compound $1, 2-$butadiene has

The hybridisation of the negatively charged carbon atoms in $(1)$ and $(2)$ are:
$(1)$ $CH_3^-$
$(2)$ $H_2C^- - CHO - CH_3$

In the molecule $HC \equiv C - CH_2 - CH = CH - CH_3$,what is the type of hybridization for the $C_2 - C_3$ bond?

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