In the part of an a.c. circuit as shown,the r | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) For the given part of the circuit containing an inductor $L$ and a resistor $R$ in series,the potential difference between points $A$ and $B$ is g

Vedclass · Accepted Answer

$0.05$

Vedclass · Answer

(D) For the given part of the circuit containing an inductor $L$ and a resistor $R$ in series,the potential difference between points $A$ and $B$ is given by the equation:$V_A - V_B = L \frac{dI}{dt} + IR$Given values are $V_A - V_B = 0.5 \ V$,$I = 0.5 \ A$,$R = 0.2 \ \Omega$,and $\frac{dI}{dt} = 8 \ A/s$.Substituting these values into the equation:$0.5 = L(8) + (0.5)(0.2)$$0.5 = 8L + 0.1$$8L = 0.5 - 0.1$$8L = 0.4$$L = \frac{0.4}{8} = 0.05 \ H$Therefore,the inductance of the coil is $0.05 \ H$.

In the part of an a.c. circuit as shown,the resistance $R=0.2 \ \Omega$. At a certain instant,$(V_{A}-V_{B})=0.5 \ V$,$I=0.5 \ A$ and $\frac{dI}{dt}=8 \ A/s$. The inductance of the coil is (in $H$)

Similar Questions

$A$ branch of a circuit is shown in the figure. If the current is decreasing at the rate of $10^3 \ A \ s^{-1}$, then the potential difference between $A$ and $B$ is (in $V$)

The self-inductance $L$ of a solenoid of length $\lambda$ and area of cross-section $A$ with a fixed number of turns $N$ increases as

What length of a very thin wire is required to obtain a solenoid of length $l_0$ and inductance $L$?

The magnetic flux through a circuit carrying a current of $2.0\,A$ is $0.8\,Wb$. If the current reduces to $1.5\,A$ in $0.1\,s$,the induced $emf$ is......$V$.

Current in a circuit falls from $5.0 \ A$ to $0.0 \ A$ in $0.1 \ s$. If an average emf of $100 \ V$ is induced,then the value of self-inductance of the circuit is . . . . . . . (in $H$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module