In the presence of peroxide,styrene reacts wi | vedclass

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(A) The reaction sequence is as follows:$1$. Styrene $(C_6H_5CH=CH_2)$ reacts with $HBr$ in the presence of peroxide via anti-Markovnikov addition to

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(A) The reaction sequence is as follows:$1$. Styrene $(C_6H_5CH=CH_2)$ reacts with $HBr$ in the presence of peroxide via anti-Markovnikov addition to form $1-$bromo$-2-$phenylethane ($X$,$C_6H_5CH_2CH_2Br$).$2$. $X$ reacts with $Mg$ in dry ether to form the Grignard reagent $C_6H_5CH_2CH_2MgBr$. This reacts with $CO_2$ followed by hydrolysis to yield $3-$phenylpropanoic acid ($Y$,$C_6H_5CH_2CH_2COOH$).$3$. $Y$ reacts with $PCl_5$ to form $3-$phenylpropanoyl chloride $(C_6H_5CH_2CH_2COCl)$.$4$. $3-$phenylpropanoyl chloride undergoes Rosenmund reduction with $H_2, Pd-BaSO_4$ to form $3-$phenylpropan$-1-$al ($Z$,$C_6H_5CH_2CH_2CHO$).The structure of $Z$ corresponds to the image provided in option $A$.

In the presence of peroxide,styrene reacts with $HBr$ to give $X$. When $X$ is reacted with magnesium in dry ether followed by $CO_2$ and hydrolysis,it gives $Y$. Treatment of $Y$ with $PCl_5$ and then with $H_2, Pd-BaSO_4$ gives $Z$. What is $Z$?

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