In the process of electroplating,m g of silv | vedclass

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(B) According to Faraday's first law of electrolysis,the mass deposited $W$ is directly proportional to the charge $Q$ $(W = ZIt)$.Therefore,$\frac{W_

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$\frac{m}{2}$

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(B) According to Faraday's first law of electrolysis,the mass deposited $W$ is directly proportional to the charge $Q$ $(W = ZIt)$.Therefore,$\frac{W_1}{W_2} = \frac{I_1 	imes t_1}{I_2 	imes t_2}$.Given: $W_1 = m$,$I_1 = 4 \ A$,$t_1 = 2 \ 	ext{minutes} = 120 \ 	ext{seconds}$.Given: $I_2 = 6 \ A$,$t_2 = 40 \ 	ext{seconds}$.Substituting the values: $\frac{m}{W_2} = \frac{4 	imes 120}{6 	imes 40}$.$\frac{m}{W_2} = \frac{480}{240} = 2$.$W_2 = \frac{m}{2} \ g$.

In the process of electroplating,$m \ g$ of silver is deposited when $4 \ A$ of current flows for $2 \ \text{minutes}$. The amount (in $g$) of silver deposited by $6 \ A$ of current flowing for $40 \ \text{seconds}$ will be:

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