In the random experiment of tossing two unbia | vedclass

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(B) The total number of outcomes when tossing two dice is $n(S) = 6 	imes 6 = 36$.For event $E$ (sum is $8$): The outcomes are $\{(2,6), (3,5), (4,4)

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Neither $I$ nor $II$ is true

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(B) The total number of outcomes when tossing two dice is $n(S) = 6 	imes 6 = 36$.For event $E$ (sum is $8$): The outcomes are $\{(2,6), (3,5), (4,4), (5,3), (6,2)\}$. Thus,$n(E) = 5$ and $P(E) = \frac{5}{36}$. So,statement $I$ is false.For event $F$ (even numbers on both dice): The possible even numbers on a die are $\{2, 4, 6\}$. The outcomes are $\{(2,2), (2,4), (2,6), (4,2), (4,4), (4,6), (6,2), (6,4), (6,6)\}$. Thus,$n(F) = 9$ and $P(F) = \frac{9}{36} = \frac{1}{4}$. So,statement $II$ is false.Therefore,neither $I$ nor $II$ is true.

In the random experiment of tossing two unbiased dice,let $E$ be the event of getting the sum $8$ and $F$ be the event of getting even numbers on both the dice. Then:
$I. P(E) = \frac{7}{36}$
$II. P(F) = \frac{1}{3}$
Which of the following is a correct statement?

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In the random experiment of tossing two unbiased dice,let $E$ be the event of getting the sum $8$ and $F$ be the event of getting even numbers on both the dice. Then:$I. P(E) = \frac{7}{36}$$II. P(F) = \frac{1}{3}$Which of the following is a correct statement?