In the reaction P + NaOH to PH_3 + NaH_2PO_2 | vedclass

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Question

(C) In the reaction $P + NaOH 	o PH_3 + NaH_2PO_2$,the oxidation state of phosphorus $(P)$ changes from $0$ in $P$ to $-3$ in $PH_3$ and $+1$ in $NaH

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$P$ is oxidized as well as reduced

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(C) In the reaction $P + NaOH 	o PH_3 + NaH_2PO_2$,the oxidation state of phosphorus $(P)$ changes from $0$ in $P$ to $-3$ in $PH_3$ and $+1$ in $NaH_2PO_2$.Since the oxidation state of $P$ both decreases and increases,it undergoes both reduction and oxidation.This is a disproportionation reaction where $P$ is simultaneously oxidized and reduced.

In the reaction $P + NaOH \to PH_3 + NaH_2PO_2$

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