In the reaction B_2H_6 + 2KOH + 2X to 2Y + 6H | vedclass

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(D) The reaction of diborane $(B_2H_6)$ with potassium hydroxide $(KOH)$ in the presence of water $(H_2O)$ is a redox reaction. The balanced chemical

Vedclass · Accepted Answer

$H_2O$,$KBO_2$

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(D) The reaction of diborane $(B_2H_6)$ with potassium hydroxide $(KOH)$ in the presence of water $(H_2O)$ is a redox reaction. The balanced chemical equation is: $B_2H_6 + 2KOH + 2H_2O 	o 2KBO_2 + 6H_2$. Comparing this with the given equation $B_2H_6 + 2KOH + 2X 	o 2Y + 6H_2$,we find that $X = H_2O$ and $Y = KBO_2$.

In the reaction $B_2H_6 + 2KOH + 2X \to 2Y + 6H_2$,$X$ and $Y$ are respectively

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