In the reaction LiH + AlH_3 rightarrow LiAlH_ | vedclass

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(A) In the reaction $LiH + AlH_3 \rightarrow LiAlH_4$,the $LiH$ molecule provides a hydride ion $(H^-)$ to the $AlH_3$ molecule.According to the Lewis

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Lewis acid and Lewis base

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(A) In the reaction $LiH + AlH_3 \rightarrow LiAlH_4$,the $LiH$ molecule provides a hydride ion $(H^-)$ to the $AlH_3$ molecule.According to the Lewis acid-base theory,a Lewis base is an electron pair donor,and a Lewis acid is an electron pair acceptor.Here,$LiH$ acts as a Lewis base because it donates the electron pair associated with the hydride ion $(H^-)$.$AlH_3$ acts as a Lewis acid because it accepts the electron pair from the hydride ion to complete its octet and form the $[AlH_4]^-$ complex.Therefore,$AlH_3$ is a Lewis acid and $LiH$ is a Lewis base.

In the reaction $LiH + AlH_3 \rightarrow LiAlH_4$,$AlH_3$ and $LiH$ act as:

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