In the reaction,as shown in the image,the num | vedclass

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(D) The reaction is between isobutylmagnesium bromide and methylamine. The Grignard reagent acts as a base and abstracts the acidic proton from the am

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$2$

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(D) The reaction is between isobutylmagnesium bromide and methylamine. The Grignard reagent acts as a base and abstracts the acidic proton from the amine to form an alkane.$ (CH_3)_2CHCH_2MgBr + CH_3NH_2 \rightarrow (CH_3)_2CHCH_3 + Mg(Br)NHCH_3 $The organic compound $X$ formed is isobutane,which is $2$-methylpropane,$(CH_3)_2CHCH_3$.The molecular formula of $X$ is $C_4H_{10}$.The isomers of $C_4H_{10}$ are:$1$. $n$-butane: $CH_3-CH_2-CH_2-CH_3$$2$. Isobutane ($2$-methylpropane): $CH_3-CH(CH_3)-CH_3$Thus,there are $2$ possible isomers for the organic compound $X$.

In the reaction,as shown in the image,the number of possible isomers for the organic compound $X$ is

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