In the relation: $\frac{dy}{dx} = 2\omega \sin(\omega t + \phi_0)$,the dimensional formula for $(\omega t + \phi_0)$ is:

Dimensions of resistance in an electrical circuit in terms of dimension of mass $M$,of length $L$,of time $T$,and of current $I$ would be:

The dimensional formula of permeability of free space $\mu_0$ is

The dimensional formula of $\frac{1}{2}\epsilon_0 E^2$ ($\epsilon_0 = $ permittivity of vacuum and $E = $ electric field) is $M^a L^b T^c$. The value of $2a - b + c$ is . . . . . . .

If $\varepsilon_0$ and $\mu_0$ represent the permittivity and permeability of free space respectively, then the dimension of the product $\varepsilon_0 \mu_0$ is,

Define dimensional formula and dimensional equation by using suitable examples.