In the rock salt structure,the number of form | vedclass

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(D) In $NaCl$ (rock salt) structure:Number of $Na^{+}$ ions $= 12$ (at edge centers) $	imes \frac{1}{4} + 1$ (at body center) $	imes 1 = 3 + 1 = 4$.

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(D) In $NaCl$ (rock salt) structure:Number of $Na^{+}$ ions $= 12$ (at edge centers) $	imes \frac{1}{4} + 1$ (at body center) $	imes 1 = 3 + 1 = 4$.Number of $Cl^{-}$ ions $= 8$ (at corners) $	imes \frac{1}{8} + 6$ (at face centers) $	imes \frac{1}{2} = 1 + 3 = 4$.Since there are $4$ $Na^{+}$ ions and $4$ $Cl^{-}$ ions per unit cell,the number of formula units per unit cell is $4$.

In the rock salt structure,the number of formula units per unit cell is equal to

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