(B) Let the number of $\alpha$-particles emitted be $x$ and the number of $\beta$-particles emitted be $y$.The change in mass number is due only to $\

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(B) Let the number of $\alpha$-particles emitted be $x$ and the number of $\beta$-particles emitted be $y$.The change in mass number is due only to $\alpha$-particles,as each $\alpha$-particle reduces the mass number by $4$.$4x = 238 - 206 = 32$$x = 8$The change in atomic number (charge) is given by $2x - y = 92 - 82$,where $2x$ is the decrease due to $\alpha$-decay and $y$ is the increase due to $\beta$-decay.$2(8) - y = 10$$16 - y = 10$$y = 6$Thus,the number of $\alpha$-particles is $8$ and the number of $\beta$-particles is $6$.

Class 12 Physics Nuclei Properties of Alpha, Beta and Gamma Rays and Decay Process

Difficult

In the uranium radioactive series,the initial nucleus is $_{92}U^{238}$ and the final nucleus is $_{82}Pb^{206}$. When the uranium nucleus decays to lead,the number of $\alpha$-particles emitted is $x$ and the number of $\beta$-particles emitted is $y$. Find $x$ and $y$.

A
$6, 8$
B
$8, 6$
C
$16, 6$
D
$32, 12$

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Class 12 Questions

Class 12

Physics Questions

Chapter

Nuclei

Subtopic

Properties of Alpha, Beta and Gamma Rays and Decay Process

$A$ radioactive nucleus undergoes $\alpha$-emission to form a stable element. What will be the recoil velocity of the daughter nucleus if $V$ is the velocity of $\alpha$-emission and $A$ is the atomic mass of the radioactive nucleus?

MediumAIIMS 2004

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$A$ radioactive element ${ }_{92}^{242} X$ emits two $\alpha$ particles,one electron and two positrons. The product nucleus is represented by ${ }_{P}^{234} Y$. The value of $P$ is

MediumMHT CET 2025

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What is the respective number of $\alpha$ and $\beta$ particles emitted in the following radioactive decay: $_{90}X^{200} \to _{80}Y^{168}$?

MediumAIPMT 1995

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$A$ nucleus decays by ${\beta ^ + }$ emission followed by a gamma emission. If the atomic and mass numbers of the parent nucleus are $Z$ and $A$ respectively, the corresponding numbers for the daughter nucleus are respectively.

Easy

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The ${ }_{92}^{238} U$ atom disintegrates to ${ }_{84}^{214} Po$ with a half-life of $4.5 \times 10^9$ years by emitting $6$ $\alpha$-particles and $n$ electrons. Here,$n$ is:

MediumKVPY 2012

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In the uranium radioactive series,the initial nucleus is $_{92}U^{238}$ and the final nucleus is $_{82}Pb^{206}$. When the uranium nucleus decays to lead,the number of $\alpha$-particles emitted is $x$ and the number of $\beta$-particles emitted is $y$. Find $x$ and $y$.

Similar Questions

$A$ radioactive nucleus undergoes $\alpha$-emission to form a stable element. What will be the recoil velocity of the daughter nucleus if $V$ is the velocity of $\alpha$-emission and $A$ is the atomic mass of the radioactive nucleus?

$A$ radioactive element ${ }_{92}^{242} X$ emits two $\alpha$ particles,one electron and two positrons. The product nucleus is represented by ${ }_{P}^{234} Y$. The value of $P$ is

What is the respective number of $\alpha$ and $\beta$ particles emitted in the following radioactive decay: $_{90}X^{200} \to _{80}Y^{168}$?

$A$ nucleus decays by ${\beta ^ + }$ emission followed by a gamma emission. If the atomic and mass numbers of the parent nucleus are $Z$ and $A$ respectively, the corresponding numbers for the daughter nucleus are respectively.

The ${ }_{92}^{238} U$ atom disintegrates to ${ }_{84}^{214} Po$ with a half-life of $4.5 \times 10^9$ years by emitting $6$ $\alpha$-particles and $n$ electrons. Here,$n$ is:

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