In Tollen's test for aldehyde,the overall num | vedclass

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(B) The oxidation of an aldehyde to a carboxylate ion by Tollen's reagent is represented by the following balanced chemical equation:$RCHO + 2[Ag(NH_{

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$2$

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(B) The oxidation of an aldehyde to a carboxylate ion by Tollen's reagent is represented by the following balanced chemical equation:$RCHO + 2[Ag(NH_{3})_{2}]^{+} + 3OH^{-} \rightarrow RCOO^{-} + 2Ag + 4NH_{3} + 2H_{2}O$In this reaction,the aldehyde group $(-CHO)$ is oxidized to a carboxylate group $(-COO^{-})$,which involves the loss of $2$ electrons.These $2$ electrons are transferred to the two silver ions $(Ag^{+})$ present in the Tollen's reagent,reducing them to metallic silver $(Ag^{0})$.Therefore,the total number of electrons transferred to the Tollen's reagent per aldehyde group is $2$.

In Tollen's test for aldehyde,the overall number of electron$(s)$ transferred to the Tollen's reagent formula $[Ag(NH_{3})_{2}]^{+}$ per aldehyde group to form silver mirror is $......$. (Round off to the Nearest integer)

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