In two successive years,80 and 60 students of | vedclass

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Question

(A) In the $1^{	ext{st}}$ year,the number of students appeared $= 80$.
Passing percentage $= 60 \%$.
Number of students passed in the $1^{	ext{st}

Vedclass · Accepted Answer

$68 \frac{4}{7} \%$

Vedclass · Answer

(A) In the $1^{	ext{st}}$ year,the number of students appeared $= 80$.
Passing percentage $= 60 \%$.
Number of students passed in the $1^{	ext{st}}$ year $= 60 \% 	imes 80 = 48$.
In the $2^{	ext{nd}}$ year,the number of students appeared $= 60$.
Passing percentage $= 80 \%$.
Number of students passed in the $2^{	ext{nd}}$ year $= 80 \% 	imes 60 = 48$.
Total number of students appeared in $2$ years $= 80 + 60 = 140$.
Total number of students passed in $2$ years $= 48 + 48 = 96$.
Average passing percentage rate in $2$ years $= \frac{	ext{Total students passed}}{	ext{Total students appeared}} 	imes 100 = \frac{96}{140} 	imes 100 = \frac{960}{14} = \frac{480}{7} = 68 \frac{4}{7} \%$.
Note: The provided option $B$ is $34 \frac{2}{7} \%$,which is half of the correct value. Re-evaluating the calculation,the correct result is $68 \frac{4}{7} \%$. Since the question asks for the average rate of students passed,we calculate the weighted average.

In two successive years,$80$ and $60$ students of a school appeared at the final examination,of which $60 \%$ and $80 \%$ passed respectively. The average rate of students passed (in percent) is

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