In what ratio must water be mixed with milk t | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Let the cost price $(CP)$ of $1$ litre of milk be $Rs. 1$.Since the mixture is sold at the cost price of milk,the selling price $(SP)$ of $1$ litr

Vedclass · Accepted Answer

$4:25$

Vedclass · Answer

(B) Let the cost price $(CP)$ of $1$ litre of milk be $Rs. 1$.Since the mixture is sold at the cost price of milk,the selling price $(SP)$ of $1$ litre of the mixture is $Rs. 1$.Given that the gain is $16 \%$,we can find the $CP$ of $1$ litre of the mixture using the formula: $CP = SP 	imes \frac{100}{100 + 	ext{gain} \%}$.$CP = 1 	imes \frac{100}{100 + 16} = \frac{100}{116} = \frac{25}{29}$.Using the rule of alligation:Cost of water = $0$Cost of milk = $1$Mean cost of mixture = $\frac{25}{29}$Ratio of water to milk = $(	ext{Cost of milk} - 	ext{Mean cost}) : (	ext{Mean cost} - 	ext{Cost of water})$Ratio = $(1 - \frac{25}{29}) : (\frac{25}{29} - 0) = \frac{4}{29} : \frac{25}{29} = 4 : 25$.

In what ratio must water be mixed with milk to gain $16 \%$ on selling the mixture at cost price?

Similar Questions

In what ratio must a grocer mix two varieties of tea worth ₹ $60$ a $kg$ and ₹ $65$ a $kg$ so that by selling the mixture at ₹ $68.20$ a $kg$ he may gain $10 \%$?

$A$ trader has $50 \ kg$ of sugar,a part of which he sells at $10 \%$ profit and the rest at $5 \%$ loss. He gains $7 \%$ on the whole. What is the quantity sold at $10 \%$ gain and $5 \%$ loss? (in $kg$)

$A$ dishonest trader professes to sell his article at cost price but he uses $900 \, g$ weight instead of $1 \, kg$. What is the percentage gain of the trader in this trade?

In a mixture of $25\, L$,the ratio of acid to water is $4: 1$. Another $3\, L$ of water is added to the mixture. The ratio of acid to water in the new mixture is

Vedclass Test Series

Exam Paper Generator

Online Exam Module