In which complex is the wavelength of absorbe | vedclass

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Question

(C) The wavelength of absorbed light $(\lambda)$ is inversely proportional to the crystal field splitting energy $(\Delta_o)$.
$\lambda \propto \frac

Vedclass · Accepted Answer

$[Co(CN)_6]^{3-}$

Vedclass · Answer

(C) The wavelength of absorbed light $(\lambda)$ is inversely proportional to the crystal field splitting energy $(\Delta_o)$.
$\lambda \propto \frac{1}{\Delta_o}$.
Stronger ligands cause greater crystal field splitting,resulting in a higher $\Delta_o$ and a lower wavelength of absorbed light.
The spectrochemical series for the ligands is: $Cl^{-} < H_2O < NH_3 < CN^{-}$.
Among the given complexes,$CN^{-}$ is the strongest ligand,leading to the largest $\Delta_o$ and consequently the lowest wavelength of absorbed light.
Therefore,the correct complex is $[Co(CN)_6]^{3-}$.

List-$I$ (Coordination entity)	List-$II$ (Wavelength of light absorbed in $nm$)
$A$. $[CoCl(NH_3)_5]^{2+}$	$I$. $310$
$B$. $[Co(NH_3)_6]^{3+}$	$II$. $475$
$C$. $[Co(CN)_6]^{3-}$	$III$. $535$
$D$. $[Cu(H_2O)_4]^{2+}$	$IV$. $600$

In which complex is the wavelength of absorbed light the lowest?

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