In which of the following arrangements is the | vedclass

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(B) Let us analyze each option:$1$. $Al^{3+}, Mg^{2+}, Na^{+}, F^{-}$ are isoelectronic species with $10$ electrons. For isoelectronic species,ionic s

Vedclass · Accepted Answer

$B < C < N < O$ $(1^{st} 	ext{ } IP)$

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(B) Let us analyze each option:$1$. $Al^{3+}, Mg^{2+}, Na^{+}, F^{-}$ are isoelectronic species with $10$ electrons. For isoelectronic species,ionic size increases as the nuclear charge decreases. The order $Al^{3+} $2$. The first ionization potential $(IP)$ generally increases across a period. However,$N$ has a stable half-filled $p$-orbital $(2p^3)$,making its $IP$ higher than $O$. The correct order is $B $3$. Electron affinity $(EA)$ generally increases across a period,but $Cl$ has a higher $EA$ than $F$ due to inter-electronic repulsion in the small $2p$ subshell of $F$. The order $I $4$. Metallic character increases down a group as ionization energy decreases. The order $Li < Na < K < Rb$ is correct.

In which of the following arrangements is the order $NOT$ according to the property indicated in the bracket?

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