In which of the following changes is there no | vedclass

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(D) $1$. In $C_2H_4$,$C$ is $sp^2$ hybridized,while in $C_2H_6$,$C$ is $sp^3$ hybridized.$2$. In $PCl_5$,$P$ is $sp^3d$ hybridized,while in $PCl_6^{-}

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$NH_3 + H^{+} \longrightarrow NH_4^{+}$

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(D) $1$. In $C_2H_4$,$C$ is $sp^2$ hybridized,while in $C_2H_6$,$C$ is $sp^3$ hybridized.$2$. In $PCl_5$,$P$ is $sp^3d$ hybridized,while in $PCl_6^{-}$,$P$ is $sp^3d^2$ hybridized.$3$. In $BF_3$,$B$ is $sp^2$ hybridized,while in $BF_4^{-}$,$B$ is $sp^3$ hybridized.$4$. In $NH_3$,$N$ is $sp^3$ hybridized (with one lone pair),and in $NH_4^{+}$,$N$ is also $sp^3$ hybridized (with four bond pairs and no lone pair). Thus,there is no change in the hybridisation of the central atom in this case.

In which of the following changes is there no change in the hybridisation of the central atom?

Similar Questions

Write the state of hybridisation of carbon in the following compounds and the shapes of each of the molecules:
$(a)$ $H_2C=O$
$(b)$ $CH_3F$
$(c)$ $HC \equiv N$

What type of bonds can the given electronic configuration of the excited state of $C$ form?

Which of the following statements is not correct?

Which of the following molecular geometries is not produced by $sp^3$ hybridisation?

Identify the pair of molecules in which the hybridization of the central atom is $sp^2$ with bent geometry.

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