In which of the following complexes is the ni | vedclass

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(B) To determine the oxidation state of $Ni$ in each complex:$1$. In $Ni(CO)_4$: $x + 4(0) = 0 \implies x = 0$.$2$. In $K_2NiF_6$: $2(+1) + x + 6(-1)

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$K_2NiF_6$

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(B) To determine the oxidation state of $Ni$ in each complex:$1$. In $Ni(CO)_4$: $x + 4(0) = 0 \implies x = 0$.$2$. In $K_2NiF_6$: $2(+1) + x + 6(-1) = 0 \implies 2 + x - 6 = 0 \implies x = +4$.$3$. In $[Ni(NH_3)_6](BF_4)_2$: $x + 6(0) + 2(-1) = 0 \implies x = +2$.$4$. In $K_4[Ni(CN)_6]$: $4(+1) + x + 6(-1) = 0 \implies 4 + x - 6 = 0 \implies x = +2$.Therefore,the highest oxidation state of nickel is $+4$ in $K_2NiF_6$.

In which of the following complexes is the nickel metal in the highest oxidation state?

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