In which of the following compounds will taut | vedclass

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(C) Tautomerism requires the presence of at least one $\alpha$-hydrogen atom adjacent to the carbonyl group $(C=O)$ or a similar functional group that

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p-Benzoquinone

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(C) Tautomerism requires the presence of at least one $\alpha$-hydrogen atom adjacent to the carbonyl group $(C=O)$ or a similar functional group that can migrate to the electronegative atom. $A$. $2$-pyridone has an $\alpha$-hydrogen on the nitrogen atom $(N-H)$,allowing for keto-enol tautomerism. $B$. Cyclohexa-$2,4$-dienone has $\alpha$-hydrogens at the $C-6$ position. $C$. $p$-Benzoquinone has no $\alpha$-hydrogen atoms adjacent to the carbonyl groups,as all positions are part of the conjugated system or substituted. $D$. Bicyclo$[2.2.1]$heptan-$2$-one has $\alpha$-hydrogens at the $C-1$ and $C-3$ positions. Therefore,$p$-Benzoquinone cannot exhibit tautomerism.

In which of the following compounds will tautomerism not take place?

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