In which of the following gases will the root | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The root mean square velocity $(V_{rms})$ of a gas is given by the formula: $V_{rms} = \sqrt{\frac{3RT}{M_W}}$.From this relation,it is clear that

Vedclass · Accepted Answer

Carbon dioxide

Vedclass · Answer

(B) The root mean square velocity $(V_{rms})$ of a gas is given by the formula: $V_{rms} = \sqrt{\frac{3RT}{M_W}}$.From this relation,it is clear that $V_{rms} \propto \frac{1}{\sqrt{M_W}}$,where $M_W$ is the molar mass of the gas.To have the minimum $V_{rms}$,the gas must have the maximum molar mass $(M_W)$.The molar masses are: $H_2 = 2 \ g/mol$,$O_2 = 32 \ g/mol$,and $CO_2 = 44 \ g/mol$.Since $CO_2$ has the highest molar mass among the given options,its root mean square velocity will be the minimum.

In which of the following gases will the root mean square velocity be minimum (at constant temperature)?

Similar Questions

The ratio of $r.m.s.$ velocities of oxygen and hydrogen at a given temperature is:

The respective speeds of five molecules are $2, 1.5, 1.6, 1.6$ and $1.2 \, km/s$. The most probable speed in $km/s$ is:

For a gas at a temperature $T$,the root-mean-square velocity ${v_{rms}}$,the most probable speed ${v_{mp}}$,and the average speed ${v_{av}}$ obey the relationship:

Light gases like $H_2$ and $He$ are found in negligible amounts in the atmosphere. Why?

The gas having average speed four times as that of $SO_{2}$ (molecular mass $64$) is

Vedclass Test Series

Exam Paper Generator

Online Exam Module