Which of the following represents the correct increasing order of crystal field splitting energy?

  • A
    $[CrCl_6]^{4-} < [Cr(H_2O)_6]^{2+} < [Cr(NH_3)_6]^{2+} < [Cr(CN)_6]^{4-}$
  • B
    $[CrCl_6]^{4-} > [Cr(H_2O)_6]^{2+} > [Cr(NH_3)_6]^{2+} > [Cr(CN)_6]^{4-}$
  • C
    $[Cr(H_2O)_6]^{2+} > [CrCl_6]^{4-} > [Cr(NH_3)_6]^{2+} > [Cr(CN)_6]^{4-}$
  • D
    None of these

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The metal $d-$orbitals that directly face the ligands in $K_3[Co(CN)_6]$ are:

The electronic configuration of the central metal atom/ion in $\left[ Co(CN)_6 \right]^{3-}$ is

Given below are two statements:
Statement $I$: Among $Zn$, $Mn$, $Sc$ and $Cu$, the energy required to remove the third valence electron is highest for $Zn$ and lowest for $Sc$.
Statement $II$: The correct order of the following complexes in terms of $CFSE$ is $[Co(H_2O)_6]^{2+} < [Co(H_2O)_6]^{3+} < [Co(en)_3]^{3+}$.

The degeneracy of $d-$orbitals is lost under:
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$III$. Mixed field ligand
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Choose the correct code:

Calculate the crystal field stabilization energy $(CFSE)$ in $[Co(CN)_6]^{3-}$.

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