In which of the following options are the ele | vedclass

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(C) The electron gain enthalpy becomes more negative as we move across a period,but there are exceptions due to electronic configuration and atomic si

Vedclass · Accepted Answer

$Cl > F > S > P$

Vedclass · Answer

(C) The electron gain enthalpy becomes more negative as we move across a period,but there are exceptions due to electronic configuration and atomic size.$Cl$ has the highest negative electron gain enthalpy among these elements because of its relatively larger size compared to $F$,which reduces inter-electronic repulsion.$F$ has a lower negative electron gain enthalpy than $Cl$ due to its very small size,which causes significant inter-electronic repulsion.Between $S$ and $P$,$S$ has a higher negative electron gain enthalpy than $P$ because $P$ has a stable half-filled $3p^3$ electronic configuration.Therefore,the correct order of negative electron gain enthalpy is: $Cl > F > S > P$.

In which of the following options are the elements correctly arranged with respect to their negative electron gain enthalpies?

Similar Questions

Which of the following transformations requires the least amount of energy?

For the process
$A_{(g)} + e^- \to A^{-}_{(g)};$ $\Delta H = x$
and $A^{-}_{(g)} \to A_{(g)} + e^-;$ $\Delta H = y$
Select the correct statement:

The increasing order of electron affinity for the given electronic configurations of elements is:
$I$. $1s^2 \ 2s^2 \ 2p^6 \ 3s^2 \ 3p^5$ $(Cl)$
$II$. $1s^2 \ 2s^2 \ 2p^3$ $(N)$
$III$. $1s^2 \ 2s^2 \ 2p^5$ $(F)$
$IV$. $1s^2 \ 2s^2 \ 2p^6 \ 3s^2 \ 3p^1$ $(Al)$

Which will have the maximum value of electron affinity among $O^x, O^y$ and $O^z$ ($x, y$ and $z$ are $0, -1$ and $-2$ respectively)?

The difference between electron gain enthalpies will be maximum between:

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