In which of the following reactions is an alcohol formed as the major product?

  • A
    $ (CH_3)_3N \xrightarrow{NaNO_2 + HCl} $
  • B
    Aniline reacting with $NaNO_2 + HCl$ at $0-5^{\circ}C$
  • C
    Cyclopentyl-ethylamine reacting with $NaNO_2 + HCl$
  • D
    $N$-methylaniline reacting with $NaNO_2 + HCl$

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The major product $(B)$ in this reaction is:

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Reduction of methyl isocyanide gives:

$RCONH_2$ is converted into $RNH_2$ by means of Hofmann bromamide degradation. In this reaction,$RCONHBr$ is formed from which this reaction has derived its name. Electron donating group at phenyl activates the reaction. Hofmann degradation reaction is an intramolecular reaction.
$1.$ How can the conversion of $(i)$ to $(ii)$ be brought about?
$(A)$ $KBr$
$(B)$ $KBr + CH_3ONa$
$(C)$ $KBr + KOH$
$(D)$ $Br_2 + KOH$
$2.$ Which is the rate determining step in Hofmann bromamide degradation?
$(A)$ Formation of $(i)$
$(B)$ Formation of $(ii)$
$(C)$ Formation of $(iii)$
$(D)$ Formation of $(iv)$
$3.$ What are the constituent amines formed when the mixture of $(i)$ and $(ii)$ undergoes Hofmann bromamide degradation?
Give the answer for question $1$,$2$,and $3$.

In the following reaction $X$ is
$CH_3NH_2 + X + KOH \to CH_3NC$ (highly offensive odour)

If $279 \ g$ of aniline is reacted with one equivalent of benzenediazonium chloride,the maximum amount of aniline yellow formed will be $.........$ $g$. (nearest integer)
(consider complete conversion)

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