In which of the following reactions is there | vedclass

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(C) In option $(C)$,the reaction is $BaO_2 + H_2SO_4 	o BaSO_4 + H_2O_2$. Checking the oxidation states: In $BaO_2$,$Ba$ is $+2$ and $O$ is $-1$. In

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$BaO_2 + H_2SO_4 	o BaSO_4 + H_2O_2$

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(C) In option $(C)$,the reaction is $BaO_2 + H_2SO_4 	o BaSO_4 + H_2O_2$. Checking the oxidation states: In $BaO_2$,$Ba$ is $+2$ and $O$ is $-1$. In $H_2SO_4$,$H$ is $+1$,$S$ is $+6$,and $O$ is $-2$. In $BaSO_4$,$Ba$ is $+2$,$S$ is $+6$,and $O$ is $-2$. In $H_2O_2$,$H$ is $+1$ and $O$ is $-1$. Since the oxidation states of all elements $(Ba, O, H, S)$ remain the same on both sides,there is no change in valency.

In which of the following reactions is there no change in the valency (oxidation state) of the elements?

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