In which of the following reactions is there | vedclass

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(A) Let us analyze the hybridisation of the central atom in each reaction:$A$) $NH_3+H^{+} \rightarrow NH_4^{+}$:In $NH_3$,$N$ is $sp^3$ hybridised ($

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$NH_3+H^{+} \rightarrow NH_4^{+}$

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(A) Let us analyze the hybridisation of the central atom in each reaction:$A$) $NH_3+H^{+} \rightarrow NH_4^{+}$:In $NH_3$,$N$ is $sp^3$ hybridised ($3$ bond pairs + $1$ lone pair).In $NH_4^{+}$,$N$ is $sp^3$ hybridised ($4$ bond pairs + $0$ lone pairs).There is no change in hybridisation.$B$) $PCl_3+Cl_2 \rightarrow PCl_5$:In $PCl_3$,$P$ is $sp^3$ hybridised.In $PCl_5$,$P$ is $sp^3d$ hybridised.Hybridisation changes from $sp^3$ to $sp^3d$.$C$) $BF_3+F^{-} \rightarrow BF_4^{-}$:In $BF_3$,$B$ is $sp^2$ hybridised.In $BF_4^{-}$,$B$ is $sp^3$ hybridised.Hybridisation changes from $sp^2$ to $sp^3$.$D$) $ClF_3+F_2 \rightarrow ClF_5$:In $ClF_3$,$Cl$ is $sp^3d$ hybridised.In $ClF_5$,$Cl$ is $sp^3d^2$ hybridised.Hybridisation changes from $sp^3d$ to $sp^3d^2$.Therefore,the correct option is $A$.

List-$I$ (Species)	List-$II$ (Hybrid Orbitals)
$(a)$ $SF_{4}$	$(i)$ $sp^{3}d^{2}$
$(b)$ $IF_{5}$	$(ii)$ $d^{2}sp^{3}$
$(c)$ $NO_{2}^{+}$	$(iii)$ $sp^{3}d$
$(d)$ $NH_{4}^{+}$	$(iv)$ $sp^{3}$
	$(v)$ $sp$

In which of the following reactions is there no change in the hybridisation of the central atom?

Similar Questions

What is the hybridisation of $Be$ in $BeF_2$ molecule?

The formation of molecular complex $BF_3-NH_3$ results in a change in hybridization of boron

Match List-$I$ with List-$II$ :

List-$I$ (Species) List-$II$ (Hybrid Orbitals)

$(a)$ $SF_{4}$ $(i)$ $sp^{3}d^{2}$

$(b)$ $IF_{5}$ $(ii)$ $d^{2}sp^{3}$

$(c)$ $NO_{2}^{+}$ $(iii)$ $sp^{3}d$

$(d)$ $NH_{4}^{+}$ $(iv)$ $sp^{3}$

$(v)$ $sp$

Choose the correct answer from the options given below :

Identify the compound which is polar and has the central atom in $sp^2$ hybridization.

The hybridizations of $C_2$ and $C_3$ in the molecule $H_3C-CH=C=CH-CH_3$ are respectively:

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