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(A) The bond order $(BO)$ and magnetic behavior for the given transformations are as follows:$1$. $C_2^+ (BO = 1.5, 	ext{Paramagnetic}) 	o C_2 (BO =

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$C_2^+ 	o C_2$

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(A) The bond order $(BO)$ and magnetic behavior for the given transformations are as follows:$1$. $C_2^+ (BO = 1.5, 	ext{Paramagnetic}) 	o C_2 (BO = 2, 	ext{Diamagnetic})$. Here,$BO$ increases and magnetic behavior changes.$2$. $NO^+ (BO = 3, 	ext{Diamagnetic}) 	o NO (BO = 2.5, 	ext{Paramagnetic})$. Here,$BO$ decreases.$3$. $O_2 (BO = 2, 	ext{Paramagnetic}) 	o O_2^+ (BO = 2.5, 	ext{Paramagnetic})$. Here,$BO$ increases but magnetic behavior remains the same.$4$. $N_2 (BO = 3, 	ext{Diamagnetic}) 	o N_2^+ (BO = 2.5, 	ext{Paramagnetic})$. Here,$BO$ decreases.Therefore,the correct transformation is $C_2^+ 	o C_2$.

Pair of species	Identical property
$A$. $B_2 \& O_2$	$P$. Bond order $= 2.5$
$B$. $Be_2 \& H_2^{2-}$	$Q$. Paramagnetic nature
$C$. $N_2^{+} \& N_2^{-}$	$R$. Diamagnetic nature
$D$. $O_2^{+} \& O_2^{-}$	$S$. Doesn't exist

In which of the following transformations,the bond order has increased and the magnetic behaviour has changed?

Similar Questions

Match the following:

Pair of species Identical property

$A$. $B_2 \& O_2$ $P$. Bond order $= 2.5$

$B$. $Be_2 \& H_2^{2-}$ $Q$. Paramagnetic nature

$C$. $N_2^{+} \& N_2^{-}$ $R$. Diamagnetic nature

$D$. $O_2^{+} \& O_2^{-}$ $S$. Doesn't exist

What is the number of electrons present in antibonding orbitals of $N_2$ molecule according to molecular orbital theory?

Which of the following species is not paramagnetic?

Arrange the following in the increasing order of their bond order: $O_{2}, O_{2}^{+}, O_{2}^{-}, O_{2}^{2-}$

Which of the following is not paramagnetic?

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