In Young's double slit experiment, the distance between the slits is $3 \text{ mm}$ and the slits are $2 \text{ m}$ away from the screen. Two interference patterns can be obtained on the screen due to light of wavelength $480 \text{ nm}$ and $600 \text{ nm}$ respectively. The separation on the screen between the $5^{th}$ order bright fringes of the two interference patterns is

  • A
    $2 \times 10^{-4} \text{ m}$
  • B
    $1 \times 10^{-4} \text{ m}$
  • C
    $8 \times 10^{-4} \text{ m}$
  • D
    $4 \times 10^{-4} \text{ m}$

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In Young's double-slit experiment,if $L$ is the distance between the slits and the screen upon which the interference pattern is observed,$x$ is the average distance between adjacent fringes,and $d$ is the slit separation,then the wavelength of light is given by:

Which of the following is true in $YDSE$?

In a Young's double slit experiment with slit separation $0.1\, mm$,one observes a bright fringe at angle $\frac{1}{40}\, rad$ by using light of wavelength $\lambda_1$. When the light of wavelength $\lambda_2$ is used,a bright fringe is seen at the same angle in the same setup. Given that $\lambda_1$ and $\lambda_2$ are in the visible range ($380\, nm$ to $740\, nm$),their values are:

The distance between two coherent sources is $1 \ mm$. The screen is placed at a distance of $1 \ m$ from the sources. If the distance of the third bright fringe is $1.2 \ mm$ from the central fringe, the wavelength of light used is:

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