In Young's double slit experiment,the phase d | vedclass

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Question

(D) In Young's double slit experiment,the condition for the $n^{th}$ bright fringe is given by the path difference $\Delta x = n\lambda$,where $n = 0,

Vedclass · Accepted Answer

$6\pi$

Vedclass · Answer

(D) In Young's double slit experiment,the condition for the $n^{th}$ bright fringe is given by the path difference $\Delta x = n\lambda$,where $n = 0, 1, 2, 3, ...$.For the third bright fringe,$n = 3$.The phase difference $\phi$ is related to the path difference $\Delta x$ by the formula $\phi = \frac{2\pi}{\lambda} \Delta x$.Substituting $\Delta x = n\lambda$ into the formula,we get $\phi = \frac{2\pi}{\lambda} (n\lambda) = 2n\pi$.For the third bright fringe $(n = 3)$,the phase difference is $\phi = 2 	imes 3 	imes \pi = 6\pi$ radians.Therefore,the correct option is $D$.

In Young's double slit experiment,the phase difference between the light waves reaching the third bright fringe from the central fringe is $(\lambda = 6000 \ \mathring{A})$

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