In Young's double slit experiment,the 10^{th} | vedclass

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(B) The condition for the $n^{th}$ order maximum in Young's double slit experiment is given by $y = \frac{n \lambda D}{d}$.Since the point of observat

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$14$

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(B) The condition for the $n^{th}$ order maximum in Young's double slit experiment is given by $y = \frac{n \lambda D}{d}$.Since the point of observation $y$ remains the same,the product $n \lambda$ must be constant for both sources.Therefore,$n_1 \lambda_1 = n_2 \lambda_2$.Given $n_1 = 10$,$\lambda_1 = 7000 \; \mathring{A}$,and $\lambda_2 = 5000 \; \mathring{A}$.Substituting the values: $10 	imes 7000 = n_2 	imes 5000$.$n_2 = \frac{10 	imes 7000}{5000} = \frac{70000}{5000} = 14$.Thus,the $14^{th}$ order maximum will be obtained at the same point.

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