In Young's double-slit experiment,the fringe | vedclass

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(B) The fringe width $\beta$ in Young's double-slit experiment is given by the formula: $\beta = \frac{\lambda D}{d}$,where $\lambda$ is the wavelengt

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Both $d$ and $D$ are doubled

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(B) The fringe width $\beta$ in Young's double-slit experiment is given by the formula: $\beta = \frac{\lambda D}{d}$,where $\lambda$ is the wavelength of light,$D$ is the distance between the screen and the slits,and $d$ is the distance between the two slits.For the fringe width to remain the same,the ratio $\frac{\lambda D}{d}$ must remain constant.Let's check option $B$: If both $d$ and $D$ are doubled,the new fringe width $\beta'$ is: $\beta' = \frac{\lambda (2D)}{(2d)} = \frac{\lambda D}{d} = \beta$.Thus,the fringe width remains unchanged when both $d$ and $D$ are doubled.

In Young's double-slit experiment,the fringe width will remain the same if:

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