In Young's double-slit experiment,monochromat | vedclass

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(D) When a thin glass plate of thickness $t$ and refractive index $\mu$ is placed in the path of one of the beams,an additional path difference is int

Vedclass · Accepted Answer

There will be no change in the fringe width,but the pattern shifts.

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(D) When a thin glass plate of thickness $t$ and refractive index $\mu$ is placed in the path of one of the beams,an additional path difference is introduced.This path difference is given by $\Delta x = (\mu - 1)t$.Due to this additional path difference,the entire interference pattern shifts by a distance $y = \frac{D}{d}(\mu - 1)t$ towards the side where the glass plate is placed.However,the fringe width $\beta = \frac{\lambda D}{d}$ depends only on the wavelength $\lambda$,the distance between the slits $d$,and the distance to the screen $D$.Since these parameters remain unchanged,the fringe width remains constant.Therefore,the correct option is $(d)$.

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