In the molecule CH_2=C=CH-CH_3 (where the ato | vedclass

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(A) In the molecule $CH_2=C=CH-CH_3$:Carbon-$1$ $(CH_2=)$: It is bonded to two $H$ atoms and one $C$ atom via a double bond. It has $3$ sigma bonds an

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$sp^2, sp, sp^2, sp^3$

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(A) In the molecule $CH_2=C=CH-CH_3$:Carbon-$1$ $(CH_2=)$: It is bonded to two $H$ atoms and one $C$ atom via a double bond. It has $3$ sigma bonds and $0$ lone pairs,so it is $sp^2$ hybridized.Carbon-$2$ $(=C=)$: It is bonded to two $C$ atoms via double bonds. It has $2$ sigma bonds and $0$ lone pairs,so it is $sp$ hybridized.Carbon-$3$ $(=CH-)$: It is bonded to one $C$ atom via a double bond,one $C$ atom via a single bond,and one $H$ atom. It has $3$ sigma bonds and $0$ lone pairs,so it is $sp^2$ hybridized.Carbon-$4$ $(-CH_3)$: It is bonded to one $C$ atom and three $H$ atoms via single bonds. It has $4$ sigma bonds and $0$ lone pairs,so it is $sp^3$ hybridized.Thus,the hybridization of carbon $1, 2, 3,$ and $4$ is $sp^2, sp, sp^2, sp^3$.

In the molecule $CH_2=C=CH-CH_3$ (where the atoms are numbered $1, 2, 3,$ and $4$ respectively),the hybridization of carbon $1, 2, 3,$ and $4$ are:

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