Which of the following is an incorrect match?

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Question

(C) Option $A$ is correct: Benzene reacts with $CH_3Cl$ in the presence of anhydrous $AlCl_3$ to form toluene via Friedel-Crafts alkylation.Option $B$

Vedclass · Accepted Answer

Benzene $+ CHCl_3 \xrightarrow{AlCl_3 	ext{ (Anhy.)}}$ Reimer-Tiemann reaction

Vedclass · Answer

(C) Option $A$ is correct: Benzene reacts with $CH_3Cl$ in the presence of anhydrous $AlCl_3$ to form toluene via Friedel-Crafts alkylation.Option $B$ is correct: The Gattermann-Koch reaction (often referred to as Gattermann aldehyde synthesis) involves the formylation of benzene using $CO + HCl$ or $HCN + HCl$ in the presence of $AlCl_3$.Option $C$ is incorrect: The Reimer-Tiemann reaction is specifically used for the formylation of phenols using $CHCl_3$ and $NaOH$,not benzene.Option $D$ is incorrect: The reaction of alkyl halides with $AgF$ is known as the Swarts reaction,not the Finkelstein reaction (which uses $NaI$ in acetone). Note: Both $C$ and $D$ are technically incorrect matches based on standard organic chemistry nomenclature.

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