Which of the following is the incorrect order | vedclass

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(C) To determine the bond angle,we consider hybridization,lone pairs,and electronegativity of the central and surrounding atoms. $1$. For option $A$:

Vedclass · Accepted Answer

$XeO_4 > ClO^{-}_4 > SO^{2-}_4 > CF_4$

Vedclass · Answer

(C) To determine the bond angle,we consider hybridization,lone pairs,and electronegativity of the central and surrounding atoms. $1$. For option $A$: $OCl_2$ $(111^{\circ})$,$SF_2$ $(103^{\circ})$,$AsH_3$ $(92^{\circ})$,$H_2Se$ $(91^{\circ})$. The order is correct. $2$. For option $B$: $NH_3$ $(107^{\circ})$,$PF_3$ $(96^{\circ})$,$PH_3$ $(93^{\circ})$,$H_2S$ $(92^{\circ})$. The order is correct. $3$. For option $C$: All these species ($XeO_4$,$ClO^{-}_4$,$SO^{2-}_4$,$CF_4$) have $sp^3$ hybridization and a tetrahedral geometry. In an ideal tetrahedral geometry,the bond angle is $109^{\circ} 28'$. Since all have the same geometry,their bond angles are equal. Therefore,the order $XeO_4 > ClO^{-}_4 > SO^{2-}_4 > CF_4$ is incorrect because they are all equal. Thus,option $C$ represents the incorrect order.

$List-I$ (Compound)	$List-II$ (Shape)
$A$. $BrF_5$	$I$. bent
$B$. $[CrF_6]^{3-}$	$II$. square pyramidal
$C$. $O_3$	$III$. trigonal bipyramidal
$D$. $PCl_5$	$IV$. octahedral

Which of the following is the incorrect order of bond angle?

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Which of the following has the smallest bond angle?

Match $List-I$ with $List-II$.
$List-I$ (Compound) $List-II$ (Shape)
$A$. $BrF_5$ $I$. bent
$B$. $[CrF_6]^{3-}$ $II$. square pyramidal
$C$. $O_3$ $III$. trigonal bipyramidal
$D$. $PCl_5$ $IV$. octahedral

Choose the correct answer from the options given below.

The atomic number of $Sn$ is $50$. The shape of gaseous $SnCl_{2}$ molecule is

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