Which of the following is the incorrect order | vedclass

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(C) $1$. $Pb$ $(I.E.)$ > $Sn$ $(I.E.)$: Due to the inert pair effect and poor shielding of $4f$ and $5d$ electrons,$Pb$ has a higher effective nuclear

Vedclass · Accepted Answer

$Li^{+}$ $(I.E.)$ < $O^{+}$ $(I.E.)$

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(C) $1$. $Pb$ $(I.E.)$ > $Sn$ $(I.E.)$: Due to the inert pair effect and poor shielding of $4f$ and $5d$ electrons,$Pb$ has a higher effective nuclear charge than $Sn$,making its $I.E.$ higher. This is correct.$2$. $Na^{+}$ $(I.E.)$ > $Mg^{+}$ $(I.E.)$: $Na^{+}$ has a stable noble gas configuration $(1s^2 2s^2 2p^6)$,while $Mg^{+}$ has a $3s^1$ configuration. Removing an electron from a stable octet requires significantly more energy. This is correct.$3$. $Li^{+}$ $(I.E.)$  $O^{+}$ $(I.E.)$. This is incorrect.$4$. $Be^{+}$ $(I.E.)$ < $C^{+}$ $(I.E.)$: $Be^{+}$ $(1s^2 2s^1)$ has a lower $I.E.$ than $C^{+}$ $(1s^2 2s^2 2p^1)$ because $C^{+}$ has a higher effective nuclear charge. This is correct.

Which of the following is the incorrect order of ionisation energy $(I.E.)$?

Similar Questions

Which of the following statements is incorrect?

With reference to the concept of ionisation potential,which one of the following sets is correct?

The ionization potentials of $Li$ and $K$ are $5.4 \ eV$ and $4.3 \ eV$ respectively. The ionization potential of $Na$ will be .............. $eV$.

Which is the correct order of ionization energies?

Element having highest $I.P.$ value is

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