Inductive reactance . . . . . .

Given below are two statements:
Statement-$I$: In an $AC$ circuit,the current through a capacitor leads the voltage across it.
Statement-$II$: In $AC$ circuits containing pure capacitance only,the phase difference between the current and the voltage is $\pi$.
In the light of the above statements,choose the most appropriate answer from the options given below:

If the capacitance of a pure capacitor in a $DC$ circuit is $1 \ F$,then what will be its capacitive reactance?

Let $f = 50\, Hz$ and $C = 100\, \mu F$ in an $AC$ circuit containing a capacitor only. If the peak value of the current in the circuit is $1.57\, A$,the expression for the instantaneous voltage across the capacitor will be (assuming current is $I = I_m \sin(\omega t)$):

If the current through an inductor of inductance $L$ is given by $I = I_0 \sin(\omega t)$,then the voltage across the inductor will be

The graphs given below depict the dependence of two reactive impedances $X_1$ and $X_2$ on the frequency of the alternating e.m.f. applied individually to them. We can then say that