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(D) The voltage gain $A_v$ of a common emitter amplifier is given as $1000$.In a common emitter amplifier,there is a phase shift of $\pi$ radians $(18

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$(4 \, V) \sin(\omega t - \pi/2)$

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(D) The voltage gain $A_v$ of a common emitter amplifier is given as $1000$.In a common emitter amplifier,there is a phase shift of $\pi$ radians $(180^{\circ})$ between the input and output signals.The input signal is $v_i = (0.004 \, V) \sin(\omega t + \pi/2)$.The output signal amplitude $V_0$ is given by $V_0 = A_v 	imes V_i = 1000 	imes 0.004 \, V = 4 \, V$.Due to the phase shift of $\pi$,the output signal is $v_o = 4 \sin(\omega t + \pi/2 + \pi) = 4 \sin(\omega t + 3\pi/2)$.Since $\sin(	heta + 3\pi/2) = -\cos(	heta) = \sin(	heta - \pi/2)$,the output signal is $v_o = 4 \sin(\omega t - \pi/2) \, V$.

Input signal to a common emitter amplifier having a voltage gain of $1000$ is given by $v_i = (0.004 \, V) \sin(\omega t + \pi/2)$. The corresponding output signal is

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