Inside a superconducting ring,six identical r | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Let the potential at $O$ be $V_O = E$ and the potential at $1$ be $V_1 = 0$. Due to the symmetry of the circuit with respect to the axis passing t

Vedclass · Accepted Answer

Both $(A)$ and $(B)$.

Vedclass · Answer

(D) Let the potential at $O$ be $V_O = E$ and the potential at $1$ be $V_1 = 0$. Due to the symmetry of the circuit with respect to the axis passing through $O$ and $1$,the potentials at points $2$ and $3$ must be equal,i.e.,$V_2 = V_3$. Since $V_2 = V_3$,the potential difference across the resistor $R_{23}$ is $V_2 - V_3 = 0$. Thus,no current flows through $R_{23}$. Furthermore,the circuit is symmetric about the line $O-1$. The resistors $R_{12}$ and $R_{13}$ are connected between the same potential points relative to the symmetry axis,but since $V_2 = V_3$,the current flowing through $R_{12}$ and $R_{13}$ is also zero because there is no potential drop across them relative to the input path. Specifically,the current entering at $O$ splits into three branches: $O-1$,$O-2$,and $O-3$. Since the circuit is symmetric,the current is equally divided into these three resistors. Therefore,statements $(A)$ and $(B)$ are both correct.

Inside a superconducting ring,six identical resistors each of resistance $R$ are connected as shown in the figure. Imagine a battery of $emf$ $E$ connected between points $O$ and $1$,with its positive terminal connected to $O$.

Similar Questions

Five identical resistors, each of resistance $R = 1500 \Omega$, are connected to a $300 \text{ V}$ battery as shown in the circuit. The reading of the ideal ammeter $A$ is: (in $\text{ A}$)

$A$ wire when connected to $220\,V$ mains supply has power dissipation $P_1$. Now the wire is cut into two equal pieces which are connected in parallel to the same supply. Power dissipation in this case is $P_2$. Then $P_2:P_1$ is

If the resistance of the voltmeter is $10000 \,\Omega$ and the resistance of the ammeter is $2 \,\Omega$,find the value of $R$ when the voltmeter reads $12 \,V$ and the ammeter reads $0.1 \,A$.

Consider the diagram shown below. $A$ voltmeter of resistance $150\,\Omega$ is connected across $A$ and $B$. The potential drop across $B$ and $C$ measured by the voltmeter is $...........\,V$.

In the circuit shown in the figure,the power developed across the $1 \Omega$,$2 \Omega$,and $3 \Omega$ resistances are in the ratio:

Vedclass Test Series

Exam Paper Generator

Online Exam Module