Irrespective of the source,a pure sample of water always yields $88.89\%$ mass of oxygen and $11.11\%$ mass of hydrogen. This is explained by the law of

  • A
    Conservation of mass
  • B
    Constant composition
  • C
    Multiple proportions
  • D
    Constant volume

Explore More

Similar Questions

$n_1 \ g$ of substance $X$ reacts with $n_2 \ g$ of substance $Y$ to form $m_1 \ g$ of substance $R$ and $m_2 \ g$ of substance $S$. The reaction is represented as $X + Y \rightarrow R + S$. What is the relationship between the mass of the reactants and the mass of the products?

$1.0 \ g$ of an oxide of $A$ contained $0.5 \ g$ of $A$. $4.0 \ g$ of another oxide of $A$ contained $1.6 \ g$ of $A$. The data indicate the law of:

Difficult
View Solution

An element forms two oxides containing respectively $53.33\%$ and $36.36\%$ of oxygen. These figures illustrate the law of

Difficult
View Solution

$1.7 \, g$ of silver nitrate is dissolved in $100 \, g$ of water. Another $0.585 \, g$ of sodium chloride is dissolved in $100 \, g$ of water and added to the first solution,resulting in a chemical reaction. $1.435 \, g$ of silver chloride and $0.85 \, g$ of sodium nitrate are produced. Which law is followed by the above information?

Which of the following pairs of substances illustrates the Law of Multiple Proportions?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo