Is $0.2$ a root of the equation $x^{2}-0.4=0$? Justify.
(B) To determine if $0.2$ is a root of the equation $x^{2}-0.4=0$,we substitute $x = 0.2$ into the equation.
Substituting $x = 0.2$ into the left-hand side $(LHS)$ gives:
$(0.2)^{2} - 0.4 = 0.04 - 0.4 = -0.36$.
Since the result is $-0.36$ and not $0$,the value $0.2$ does not satisfy the equation.
Therefore,$0.2$ is not a root of the equation $x^{2}-0.4=0$.
Substituting $x = 0.2$ into the left-hand side $(LHS)$ gives:
$(0.2)^{2} - 0.4 = 0.04 - 0.4 = -0.36$.
Since the result is $-0.36$ and not $0$,the value $0.2$ does not satisfy the equation.
Therefore,$0.2$ is not a root of the equation $x^{2}-0.4=0$.
Explore More
Similar Questions
Verify whether the given value of $x$ is a solution of the quadratic equation or not: $\frac{x+1}{x-1} - \frac{x-1}{x+1} = \frac{5}{6}, x = 5$
Easy
View SolutionFind the discriminant of the following quadratic equation and hence determine the nature of the roots of the equation: $x^{2} = 9$.
Easy
View SolutionState whether the quadratic equation $(x+1)(x-2)+x=0$ has two distinct real roots. Justify your answer.
Medium
View SolutionThe length of a rectangular garden exceeds its breadth by $6 \, m$. If the area of the garden is $216 \, m^2$,find the length and the breadth of the garden.
Difficult
View SolutionExamine whether the following equation is quadratic or not: $x^{2}+2 \sqrt{x}+3=0$
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo