Identify the product B in the following react | vedclass

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(B) $1$. The reaction of benzoic acid $(C_6H_5COOH)$ with $NaOH$ produces sodium benzoate $(C_6H_5COONa)$,which is compound $A$.$2$. The electrolysis

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Biphenyl

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(B) $1$. The reaction of benzoic acid $(C_6H_5COOH)$ with $NaOH$ produces sodium benzoate $(C_6H_5COONa)$,which is compound $A$.$2$. The electrolysis of sodium salts of carboxylic acids is known as the Kolbe electrolysis.$3$. In the Kolbe electrolysis of sodium benzoate,the carboxylate ion $(C_6H_5COO^-)$ undergoes oxidation at the anode to form a benzoyloxy radical $(C_6H_5COO\cdot)$,which then loses $CO_2$ to form a phenyl radical $(C_6H_5\cdot)$.$4$. Two phenyl radicals combine to form biphenyl $(C_6H_5-C_6H_5)$,which is compound $B$.

Identify the product $B$ in the following reaction sequence:
$C_6H_5COOH$ $\xrightarrow{NaOH} A$ $\xrightarrow{\text{Electrolysis}} B$

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Identify the product $B$ in the following reaction sequence:$C_6H_5COOH$ $\xrightarrow{NaOH} A$ $\xrightarrow{\text{Electrolysis}} B$